I have the following list

```
example <- list(a = c(1, 2, 3),
b = c(2, 3),
c = c(3, 4, 5, 6))
```

that I’d like to transform into the following tibble

```
# A tibble: 9 × 2
name value
<chr> <dbl>
1 a 1
2 a 2
3 a 3
4 b 2
5 b 3
6 c 3
7 c 4
8 c 5
9 c 6
```

I’ve found multiple StackOverflow questions on this subject like here, here or here, but none is adressing this particular case where the name of the vector is not expected to become a column name.

I managed to achieve the desired result with a good old loop like below, but I’m looking for a faster and more elegant way.

```
library(dplyr)
example_list <- list(a = c(1, 2, 3),
b = c(2, 3),
c = c(3, 4, 5, 6))
example_tibble <- tibble()
for (i in 1:length(example_list)) {
example_tibble <- example_tibble %>%
bind_rows(as_tibble(example_list[[i]]) %>%
mutate(name = names(example_list)[[i]]))
}
example_tibble <- example_tibble %>%
relocate(name)
```

### >Solution :

Try `stack`

```
> stack(example)
values ind
1 1 a
2 2 a
3 3 a
4 2 b
5 3 b
6 3 c
7 4 c
8 5 c
9 6 c
```