# How to get items from a list based on specific item in Python

I have below list

``````l = ['7E', '00', '10', '97', '9A', '00', '13', 'A2', '00', '41', 'B6', '13', '58', 'FF', 'FE', '41', '50', '00', '01', '28']
``````

From above list, I want to extract `41 B6 13 58`, which always comes after `00 13 A2 00` and is always length 4.

I thought of extracting this based on the index of `00` (just before `41`) but there can be many `00` in the list so this will not be always correct.

So I have to make sure its always `00 13 A2 00` and then get the index of `00` (which is after `A2`) and from this index extract next 4 items which should be the final output. But I am unable to decide how to go for it. Can anyone please help.

### >Solution :

``````for i in range(0, len(l)-8):
if l[i:i+4] == ['00', '13', 'A2', '00']:
return l[i+4:i+8]
``````

So what we are doing: looking linearly for those four given values (indices `i`, `i+1`, `i+2`, and `i+3`), and if we find them, we take the next four values from the list – indices `i+4`, `i+5`, `i+6`, and `i+7`.