I have below list

```
l = ['7E', '00', '10', '97', '9A', '00', '13', 'A2', '00', '41', 'B6', '13', '58', 'FF', 'FE', '41', '50', '00', '01', '28']
```

From above list, I want to extract `41 B6 13 58`

, which always comes after `00 13 A2 00`

and is always length 4.

I thought of extracting this based on the index of `00`

(just before `41`

) but there can be many `00`

in the list so this will not be always correct.

So I have to make sure its always `00 13 A2 00`

and then get the index of `00`

(which is after `A2`

) and from this index extract next 4 items which should be the final output. But I am unable to decide how to go for it. Can anyone please help.

### >Solution :

```
for i in range(0, len(l)-8):
if l[i:i+4] == ['00', '13', 'A2', '00']:
return l[i+4:i+8]
```

So what we are doing: looking linearly for those four given values (indices `i`

, `i+1`

, `i+2`

, and `i+3`

), and if we find them, we take the next four values from the list – indices `i+4`

, `i+5`

, `i+6`

, and `i+7`

.