# extreme Noob needs short review on "if" and "!="

Could you please take a short look and tell me what’s wrong with the code?

``````e = eval(input('enter 1 '))
f = eval(input('enter 3 '))

if e != 1 and f != 3:
print('you got it wrong!')
else:
print("correct")
``````

So the problem here is if I enter 1 of 2 numbers correct, it says that it is correct but it shouldn’t because I have an "and" operator ?

Of course I could change the code to something like this which would work fine:

``````if e == 1 and f == 3:
print('correct')
else:
print("you got it wrong!")
``````

But on the other side I would like to understand what I’m doing wrong?
Thanks 🙂

### >Solution :

`if e != 1 and f != 3:` means if `e` is wrong and `f` is also wrong. But as you mentioned, you entered one right, then the `and` statement doesn’t get through, since one of them are still right.

You need `or`:

``````if e != 1 or f != 3:
print('you got it wrong!')
else:
print("correct")
``````

Btw, I recommend you to use `int` instead of `eval` (since `eval` is bad practice, and you are converting to an integer):

``````e = int(input('enter 1 '))
f = int(input('enter 3 '))
``````