Create a counter that takes in a number from the user, counts from 0 to that number, tells the user as it counts if each number is even or odd, then sums all the numbers together and prints the sum.

The following code and comments are a starting point. The text following each # is a comment, you will need to replace the comments with the necessary code:

``````count = 0

sum = 0

num = 0

# Ask user for a number

#All code lines that need to be inside the while loop, need to be tabbed over once.

while (count <= num):

# Use the following if statement along with the remainder operator (modulus, %) to check if a number is even or odd.

if count%2!=0:

#print the number is odd

else:

#print the number is even

count = count +1 #update counter for the while loop exit condition

#print the sum
``````

### >Solution :

Using for loop

``````count=0
sum=0

for i in range(0,n+1):
if (i%2==0):
print("Number is Even")
else:
print("Number is Odd")

sum+=i

print(sum)
``````

Using While loop:

``````count=0
sum=0

while(count<n):
if(count%2==0):
print("Number is Even")
else:
print("Number is odd")

count+=1
sum+=count

print(sum)
``````