I have tried using the modulo operator for small floats and it works perfectly fine.

For example: `5 % 2`

returns `1`

.

But for other large floats that are read as exponential in python it just returns `0`

every time even if the number is odd.

Like this:

`295147905179352825855 % 2`

returns `0`

even though that number is clearly odd.

Is there anything I can do to check large floats without python reading it as exponential?

### >Solution :

What you said is **not** true. `295147905179352825855 % 2`

should work because Python does arbitrary precision math on **integers**. There’s no floating-point values in your question

OTOH if you use a **float** like `295147905179352825855.0`

then it obviously won’t work because Python uses IEEE-754 binary64 format which has only 53 bits of precision and can’t store values such as `295147905179352825855.0`

. The closest value is `295147905179352825856.0`

which is clearly an even number

```
>>> 295147905179352825855 % 2
1
>>> 295147905179352825855.0 % 2
0.0
>>> format(295147905179352825855.0, '.20f')
'295147905179352825856.00000000000000000000'
>>> 295147905179352825856.0 == 295147905179352825855.0
True
```