This is my list:

lst = [1,2,3,4,5]

If I do this:

from itertools import permutations
lst = [1,2,3,4,5]
l = []

lperm = permutations(lst,3)
for i in lperm:
    l.append(i)

print(l)

It returns this:

[(1, 2, 3), (1, 2, 4), (1, 2, 5), (1, 3, 2), ...]

But this is what I want:

[(1, 2, 3),(2, 3, 4),(3, 4, 5)]

Anyone has an answer for this?

>Solution :

l = 3
lst = [1, 2, 3, 4, 5]

print([lst[x:x+l] for x in range(len(lst)-l+1)])

or if you need those tuples:

print([tuple(lst[x:x+l]) for x in range(len(lst)-l+1)])

If you don’t want to hold all the values in the memory:

l = 3
lst = [1, 2, 3, 4, 5]


def slider(iterable, l):
    for x in range(len(iterable)-l+1):
        yield tuple(lst[x:x+l])


for i in slider(lst, l):
    print(i)