Using `% 2`

gives me the alternating sequence `[0, 1, 0, 1, ...]`

```
seq = []
for i in range(10):
e = i % 2
seq.append(e)
```

Is there a way to generate the sequence `[0, 0, 1, 1, 0, 0, 1, 1,...]`

by generating the element **from inside the loop**?

```
seq = []
for i in range(10):
e = the_solution(i)
seq.append(e)
```

### >Solution :

It sounds like you want to slow your existing sequence down, effectively doubling the length of each element. That is, indices 0 and 1 of your new sequence should correspond to index 0 of your old; 2 and 3 of your new sequence should correspond to index 1 of the old; and so on. We can use integer division to get this behavior.

```
e = (i // 2) % 2
```

`//`

is like `/`

but it rounds down to the next integer, so `2 // 2`

and `3 // 2`

are both `1`

.