I have a list `X`

. I want to print indices of `X`

which contain different list elements. For instance, `X[0]`

has some different elements, `X[1]`

has all the same elements and `X[2]`

has again different elements. I present the expected output.

```
X=[[[46.36363636363636],
[35.90909090909091],
[31.363636363636367],
[25.454545454545453],
[24.545454545454547],
[24.545454545454547],
[24.545454545454547],
[24.545454545454547],
[24.545454545454547],
[24.545454545454547]],
[[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636],
[46.36363636363636]],
[[46.36363636363636],
[39.09090909090909],
[37.27272727272727],
[35.0],
[33.18181818181819],
[32.72727272727273],
[32.27272727272727],
[32.27272727272727],
[32.27272727272727],
[32.27272727272727]]]
for i in range(0,len(X)):
X = [x for x in X if min(x) != max(x)]
```

The expected output is

```
i=[0,2]
```

### >Solution :

Loop over every list in your list, and check if each list contains only the same elements. If they don’t, return the index of the list.

```
res = [x for x, y in enumerate(X) if not all(e == y[0] for e in y)]
print(res)
>>> [0, 2]
```