I have a 2D array of 5*5 like this:

```
>>> np.random.seed(100)
>>> a = np.random.randint(0,100, (5,5))
>>> a
array([[ 8, 24, 67, 87, 79],
[48, 10, 94, 52, 98],
[53, 66, 98, 14, 34],
[24, 15, 60, 58, 16],
[ 9, 93, 86, 2, 27]])
```

if I have an initial position, is there any way to quickly and easily get the values of its four neighbors around it? The method I’m using now is a bit cumbersome:

Suppose the current position is [x, y] (if x=2, y=3 then the value in the array is 14,)，then the position above it is [x-1, y], the bottom is [x+1, y], the left side is [y-1, x], and the right side is [y+1, x]. I use the following four lines of code to get the values of neighbors.

```
curr_val = a[2,3]
up_val = a[2+1, 3]
bott_val = a[2-1, 3]
left_val = a[2, 3+1]
right_val = a[2, 3-1]
```

So my question is is there a more convenient function in numpy that can do this and even query the values of four neighbors at once?

### >Solution :

You can also use:

```
mask = np.array([[0, 1, 0],
[1, 0, 1],
[0, 1, 0]]).astype(bool)
a[i-1:i+2, j-1:j+2][mask]
```

output:

```
array([53, 93, 94, 86])
```