Not sure if looking at code all day is making me blind, beside my natural ignorance, but I can’t find out why I cannot get the inner look to throw its next item into finalDataset. The intent is to generate a new array with some modifications. Appreciate any help.
const arr1 = [
["Header1", "Color", "Size"],
["Data1", "Blue", 16],
["Data2", "Red", 20],
["Data3", "Brown", 5],
]
const arr2 = [
["Name", "CorrectedColor", "Style"],
["Nike", "Black", "Rock"],
["Puma", "Purple", "Country"],
["ShingLing", "White", "Romantic"],
]
let finalDataset = [];
for (let a = 1; a < arr1.length; a++) {
let newRow = arr1[a];
for (let n = 1; n < arr2.length; n++) {
newRow[0] = arr2[n][1];
newRow[1] = arr2[n][2];
newRow[2] = '-'
console.log(newRow)
finalDataset.push(newRow)
}
}
console.log(finalDataset)>Solution :
You’re pushing references to the same array into finalDataset, so they all take the same value (and you’re changing arr1 while you’re at it – check with console.log(arr1) after your code completes). You can work around this by making copies of the arrays, e.g. using slice (you could also use e.g. [...newRow]):
const arr1 = [
["Header1", "Color", "Size"],
["Data1", "Blue", 16],
["Data2", "Red", 20],
["Data3", "Brown", 5],
]
const arr2 = [
["Name", "CorrectedColor", "Style"],
["Nike", "Black", "Rock"],
["Puma", "Purple", "Country"],
["ShingLing", "White", "Romantic"],
]
let finalDataset = [];
for (let a = 1; a < arr1.length; a++) {
let newRow = arr1[a].slice(0);
for (let n = 1; n < arr2.length; n++) {
newRow[0] = arr2[n][1];
newRow[1] = arr2[n][2];
newRow[2] = '-'
finalDataset.push(newRow.slice(0))
}
}
console.log(finalDataset)