# Create a function that, given an array and declared a variable, returns true or false if the variable exceeds each element of the array

I would like to create a program from a function that, given an array made up of a series of numbers and declared a variable with a value, returns true if the value exceeds each of the numbers in array and otherwise returns false.

``````let array = [5000, 5000, 3]
let value = 2300;

function compare_Values(table,number){

for(let i = 0; i <= table.length; i++){

if(number < table[i]){

var result = "TRUE: if passed";

} else{
var result = "FALSE: failed";
}
return result
}
}

console.log(compare_Values(array,value))
``````

I don’t know why the result returns TRUE. The value does not exceed each of the elements in the table.
Can someone help me? I don’t know where is my mistake.

### >Solution :

If I understood it correctly, then there are lots of ways to solve this problem, but I’ll show you 2 of them.

By using a common for loop — you just initialize a result (`res`) outsite the for loop and then stops the iteration if any element is lower than the `n`

``````function solve(arr, n) {
let res = true;
for (let i = 0; i < arr.length && res; i++) {
res = n <= arr[i];
}

return res;
}
``````

By using the `Array.prototype.every()` method:

``````let arr = [5000, 5000, 4000];
let n = 2300;

console.log(arr.every(v => n <= v));
``````