I’m trying to improve my algorithm skills. When I run my code, I get an "Execution Timed Out" error.

# Pseudocode

```
[This is writen in pseudocode]
if(number is even) number = number / 2
if(number is odd) number = 3*number + 1
```

# My Code

```
def hotpo(n):
calculator = 0
while n >= 1:
if n % 2 == 0:
n = n / 2
else:
n = 3 * n + 1
calculator = calculator + 1
return calculator
```

### >Solution :

you are dividing number by 2 if number is even but multiplying it by 3 and adding 1 into it.

so for any number it will keep doing this

2,1,4,2,1,4,2,1,4,2,1,4,2,1,4,…..

you just have to change condition to `n>1`

in while loop

because at last 2 will come and it got divided by 2, then n becomes 1 then again it will consider 1 as odd as per your condition then again 1*3+1=4 and again 4/2=2 and so on…

I hope you understood..