why this line of code has error message ?

Random ran2 = new Random();
float distance = ran2.nextFloat(50f);

>Solution :

The method nextFloat(float) is implemented in interface java.util.random.RandomGenerator (docs.oracle.com), which was introduced in Java 17. Compiling this code with a JDK < 17 will result in a compilation error:

...
... error: method nextFloat in class Random cannot be applied to given types;
...

There are two ways to solve this issue:

• Upgrade to a JDK >= 17 (the recommended approach)

• Copy what RandomGenerator.nextFloat(float) does (the actual implementation can be found in jdk.internal.util.random.RandomSupport (github.com)):

  float distance = ran2.nextFloat();
  distance = distance * 50f;
  if (distance >= 50f) // may need to codistancedistanceect a distanceounding pdistanceoblem
    distance = Float.intBitsToFloat(Float.floatToIntBits(50f) - 1);