Advertisements
Given this sample data:
| temp |
|---|
| a. b |
| a b |
| a. b. c |
| ab.c |
I only want to keep rows in column temp that has only one period, so the above data would become:
| temp |
|---|
| a. b |
| ab.c |
Is there a way to do this with a lambda function, preferably?
>Solution :
You can try this:
df.loc[df['temp'].str.count(r'\.').eq(1)]
temp
0 a. b
3 ab.c