I have got a list:

```
first = [100, 110, 60]
```

How to make that: if the next number is greater than the previous one, then it is necessary to reduce this number like preceding number.

For example, the answer should be:

```
ans = [100, 100, 60]
```

The second example:

```
arr = [60,50,60]
ans = [60, 50, 50]
```

The third example:

```
arr = [20, 100, 150]
ans = [20, 20, 20]
```

I try to, but i think it’s not good idea

```
for i in range(len(arr)-1):
if arr[i] < arr[i+1]:
answer.append(a[i+1] - 10)
if arr[i] < arr[i+1]:
answer.append(a[i])
if arr[i] < arr [i+1]:
answer.append(arr[-1])
```

### >Solution :

This will modify the list *in situ*:

```
def fix_list(_list):
for i, v in enumerate(_list[1:], 1):
_list[i] = min(v, _list[i-1])
return _list
print(fix_list([100, 110, 60]))
print(fix_list([60, 50, 60]))
print(fix_list([20, 100, 150]))
```

**Output:**

```
[100, 100, 60]
[60, 50, 50]
[20, 20, 20]
```