Sorry for bad English .

I was trying to write a program that gets a number and see if the digits of an entered number are repeated or not . I did try to if(analyse[0]==analyse[1]==analyse[2]==…) but since I don’t know exactly how many elements will array have, it didn’t work

```
#include<iostream>
int main(){
int number,number_help;
const int count{10};
std::cin>>number;
number_help = number ;
int digitcount{0};
while(number_help>0){
number_help/=10;
digitcount+=1;
}
int analyse[count]{};
for(size_t i {0}; i<digitcount ; i++){
analyse[i] = number%10;
number/=10;
}
//I don't know what to code here
return 0;
}
```

### >Solution :

Change your approach: count how many there are of each digit instead of comparing them to each other.

This is much simpler.

Example:

```
#include<iostream>
int main(){
int number;
std::cin >> number;
const int count{10};
int frequency[count]{};
do {
frequency[number % 10] += 1;
number /= 10;
} while (number != 0);
for (int i{0}; i < count; i++) {
if (frequency[i] > 1) {
std::cout << i << " was repeated " << frequency[i] << " times.\n";
}
}
}
```