So I am new to Haskell and below I have attempted to program a function that takes a given value of e and a given list and determines whether that given value appears in the list given outputting True if the value given does appear and False if not.
inListm e  = False inListm e (x:xs) | e == x = True || inListm e xs | otherwise = False || inListm e xs
inListm 2 [0, 2, 1, 2]
is given, the output would be
However, I would like the final output to be in a list like this
I have attempted to do this by
inListd e  = False :  inListd e (x:xs) | e == x = True :  || inListd e xs | otherwise = False : || inListd e xs
but all that gives me is an error so I would like to know how I could resolve this
You are on the right track. The only thing necessary is to return a list if you have a result, so:
inListd :: Eq a => a -> [a] -> [Bool] inListd e  = [False] inListd e (x:xs) | e == x = [True] | otherwise = inListd e xs
That being said, I does not seem to make much sense to wrap the result in a list.