I am supposed to create a function that takes some functions as arguments, and returns a composition of those arguments in the following way:

Given functions fnN, fn(N-1), …, fn1, and a value v, the function should return the result of

```
compose(fnN, fnN-1, ..., fn1)(v) = fnN(fnN-1(...(fn1(v))));
```

I would be grateful if someone can help out and answer why this method doesn’t:

```
function compose(...fns) {
return function composed(v) {
if (fns.length >= 2) {
return fns[0](compose(...fns.slice(1)));
} else return fns[0](v);
}
}
```

Thank you!

I know that this solution works for example:

```
function compose(...fns) {
return function(v) {
for (let fn of fns) {
v = fn(v);
}
return v;
}
}
```

### >Solution :

You need to fix you recursive call to call the resulting function with a given argument.

```
function compose(...fns) {
return function composed(v) {
const [first, ...rest] = fns;
if (!rest.length) return first(v)
return first(compose(...rest)(v))
}
}
function inc(x) { return x + 1 }
console.log(compose(inc, inc, inc)(0))
```