# I am trying to create a code to simulate a lottery game. I need to check if one of the generated numbers already has been generated before

I already have a working code but I noticed that sometimes 2 or more of the same numbers would be generated in a list and therefore mess up the whole game. I am not very experienced in python so I have no clue on how to check if the number has been used on the list and if so, on how to generate a new, unused one!

I need a new piece of code to check for this problem and if it happens, to regenerate the number.
Here is my existing code:

``````import random

luckynumber = []
inputnumber = []

correct_numbers = 0

print('Welcome to the game!')
print('Please insert 6 numbers from 1 to 49:')

for number in range(0, 6):
randomnumber = random.randint(1, 49)
luckynumber.append(randomnumber)

for number in range(0, 6):
player_number = int(input())
inputnumber.append(player_number)

for correctnumber in luckynumber:
for player_number in inputnumber:
if player_number == correctnumber:
correct_numbers = correct_numbers + 1

print(f'You gessed {correct_numbers} correct numbers!')
print(f'Original correct numbers: {luckynumber}')
``````

### >Solution :

`random.sample` will give you a sample of k random elements from a population, with each element guaranteed to be different. So you can do that and not have to worry about finding and replacing duplicates.

``````luckynumber = random.sample(range(1, 50), 6)
Note that `randint(1, 49)` gives you numbers between 1 and 49 inclusive, but `range` gives a range of numbers that excludes that last element. So here we have `range(1, 50)` to select from the numbers 1-49 inclusive.