I have a dataframe with a column with many different-sized lists.I would like to compare it with a second column preferably without expending a column_of_lists to multiple columns.

| value | column_of_lists |
| --- | --- |
| 1 | \[1,2,1,1\] |
| 3 | \[3\] |
| 1 | \[4,4\] |
| 3 | \[0\] |

to

I tried

df.loc[df['value'].isin(df['column_of_lists']), 'is_in_column_of_lists'] = True

but I got

>Solution :

Use df.apply with in operator:

df['is_booked'] = df.apply(lambda x: x['value'] in x['column_of_lists'], axis=1)

---

   value column_of_lists  is_booked
0      1    [1, 2, 1, 1]       True
1      3             [3]       True
2      1          [4, 4]      False
3      3             [0]      False