I have an array `arr = [[[1, 2], [3, 4]], [5, 6]]`

.

I am looking for a function f that returns me the indexes of the elements also in the nested array given only `arr`

as input.

For example, `function(arr, 2) -> (0, 0, 1)`

Has some library implemented it?

Of course it’s not a problem if the array is a numpy array.

### >Solution :

For this you dont necessarely need a special library, you can use the `numpy`

where function, like this:

```
import numpy as np
def find_indices(arr, x):
indices = np.where(np.array(arr) == x)
return tuple(indices[0])
# example usage
arr = [[[1, 2], [3, 4]], [5, 6]]
print(find_indices(arr, 2)) # output: (0, 0, 1)
```

edit: my code seem to fail on some case with the error `ValueError: setting an array element with a sequence. The requested array has an inhomogeneous shape after 2 dimensions. The detected shape was (2, 2) + inhomogeneous part.`

here is a version that work without `numpy`

```
def find_indices(arr, value):
for i, sublist in enumerate(arr):
for j, subsublist in enumerate(sublist):
for k, item in enumerate(subsublist):
if item == value:
return i, j, k
return None
arr = [[[1, 2], [3, 4]], [5, 6]]
print(find_indices(arr, 2)) # Output: (0, 0, 1)
```