Below in the first function I return the square root of any value passed as the argument and it is working fine when I call it and in the second function at the part of `mysqrt`

variable it doesn’t return the `mysqrt(num)`

returns a value of none, so it gives an error at the `diff`

variable while the value of `mysqrt(a)`

is none.

```
import math
epsilon = 0.0000001
def my_sqrt(a):
x = a/2
while True:
y = (x + a/x) / 2
if y == x:
return print(y)
break
x = y
def test_sqrt(a):
num = 1
while a >= num:
a_value = f"a = {num} |"
mysqrt = f"my_sqrt(a) = {my_sqrt(num)} |"
mathsqrt = f"math.sqrt(a) = {math.sqrt(num)} |"
diff = f"diff = {my_sqrt(num) - math.sqrt(num)}"
print(a_value, mysqrt, mathsqrt, diff)
num = num + 1
test_sqrt(3)
```

I tried to hard code it to the print function but it doesn’t work, and I am expected that it returns a value instead of none.

### >Solution :

I think the problem is that you are returning the result of the `print`

statement. you should refactor it like:

```
print(y)
return y
```