Reduce the total number of "break" and "continue" statements in this loop to use one at most in Javascript

Advertisements I am refactoring code written by another developer. On SonarQube, the error thrown is that I need to "Reduce the total number of "break" and "continue" statements in this loop to use one at most". I’m trying to refactor the code so that it logically makes sense but without the use of continue. As… Read More Reduce the total number of "break" and "continue" statements in this loop to use one at most in Javascript

(cs50)not getting output for the given code. can anyone please check this out?

Advertisements my code counts the number of letters from the given string(excluding white space). cs50.h is a library which consists of get_string() function which takes input from user. the code is compiling but when i give an input which has more than one word, it stops working(doesn’t give me anything).can anyone please tell why?(i am… Read More (cs50)not getting output for the given code. can anyone please check this out?

Continue in if conditional python loop is not working

Advertisements a = [‘AKDYYDSSGYHFDY’, ‘AKDDSSGYYFYFDY’, ‘AKDAGDYYYYGMDV’] match = [‘DS’, ‘DV’, ‘DY’] counter = 0 for i in a: for j in match: if j in i: print(i, j) counter = counter+1 continue print(counter) Results are AKDYYDSSGYHFDY DS AKDYYDSSGYHFDY DY AKDDSSGYYFYFDY DS AKDDSSGYYFYFDY DY AKDAGDYYYYGMDV DV AKDAGDYYYYGMDV DY 6 I was expecting that it would identify… Read More Continue in if conditional python loop is not working

Python: Filling a dataframe sequentially based on matching ids (inefficient code)

Advertisements Tables and code at the bottom will probs help much more than description. I have a solution that works but think its very inefficient see bottom. Problem: I have two data frames df_1 and df_2 — these dataframes have a match column – match_id df_2 has a date column that I am trying to… Read More Python: Filling a dataframe sequentially based on matching ids (inefficient code)

continue loop even if one host is not available

Advertisements import time import paramiko import sys from getpass import getpass #First Unifi AP IP Address firstip=3 fistdigits = ‘10.0.0.’ #how can we prevent from crashing if 10.0.0.19 is not an available device while firstip<=100: host= f'{fistdigits}{firstip}’ #first one will be 10.0.0.3 then 10.0.0.4 etc username="username" password="password" session= paramiko.SSHClient() session.set_missing_host_key_policy(paramiko.AutoAddPolicy()) session.connect(hostname=host, username=username, password=password) #upgradeurl="https://dl.ui.com/unifi/firmware/U7PG2/4.3.13.11253/BZ.qca956x.v4.3.13.11253.200430.1420.bin&quot; #stdin,… Read More continue loop even if one host is not available