Advertisements I want the difference of column ‘position’ by the column ‘Seg’ with ‘x’ adjacent. import numpy as np import pandas as pd mydict = {‘position’:[‘0.0’, ‘0.433’, ‘2.013’, ‘3.593’, ‘5.173’, ‘6.753’, ‘6.9’],’Seg’:[‘x’, ‘x’, np.nan, np.nan, np.nan, np.nan, ‘x’]} df = pd.DataFrame.from_dict(mydict) df position Seg 0 0.0 x 1 0.433 x 2 2.013 NaN 3 3.593… Read More Dataframe – difference of rows by some style

Advertisements I’m using a dataset from an R package track2KBA which has tracking data on a seabird species. I want to measure the time difference between each relocation grouped by the individual bird. But when I run my script I don’t get the differences I’d expect. For instance, the first difference should be 6 seconds.… Read More Why are my time differences not coming out as expected in R?

Advertisements I have 2 lists: list1 = [ { "address": "1000", "amount": 0 }, { "address": "2000", "amount": 0 }, { "address": "3000", "amount": 0 }, { "address": "4000", "amount": 20 } ] list2 = [ { "account": "1000", "balance": 100 }, { "account": "2000", "balance": 200 }, { "account": "3000", "balance": 300 } ]… Read More Find different values between 2 lists of dictionaries with different keys

Advertisements I need to get a DataFrame with column difference of column that I choose (for example the last one) I tried using df.diff(axis=1, periods=1) will count column difference with the next column. However, I want to get difference of columns with exactly one column (last one). >Solution : Use DataFrame.sub for subtract by last… Read More How to get difference of columns in DataFrame Pandas?

Advertisements i have this audit table User date text text 2 u1 2023-01-01 hi yes u1 2022-12-20 hi no u1 2022-12-01 hello maybe And i need as a result, something like this: User date text text 2 u1 2023-01-01 null x u1 2022-12-20 x x u1 2022-12-01 null null So i can know wich column… Read More In PostgreSQL, how can I optimize a query with which I obtain the differences between the current column and the immediately previous one?

Advertisements i am interested in generating efficient c/c++ code to get the differences between two time series. More precise: The time series values are stored as uint16_t arrays with fixed and equal length == 128. I am good with a pure c as well as a pure c++ implementation. My code examples are in c++… Read More C/C++ fast absolute difference between two series

Advertisements So, I am trying to turn a number to binary, which seems fine in both javascript and python, but my issue is that when I do so, they both return a different binary string. I enter: 585190997647163394 JavaScript returns: 100000011111000001000001110010100100100001000000000000000000 Python returns: 100000011111000001000001110010100100100001000000000000000010 If you can´t see the difference, the penultimate digit in the… Read More Different binary outputs from js and py

Advertisements Suppose I have a reverse-sorted list of doubles: {3, 2, 1} I want to find the sum of all the positive differences between possible pairs of numbers. In this case, that would be (3-2)+(3-1)+(2-1) = 4. I know that going through all the pairs is an option, but this takes O(n^2) time. Any idea… Read More Difference of all possible pairs of numbers in an array

Advertisements I am trying to find the time (in days) until next occurrence of each specific value. For example, say I have the data below: column1 created_at 0 A 2018-09-03 1 B 2018-09-07 2 B 2018-09-08 3 A 2018-09-09 4 B 2018-09-12 The goal is to get time difference for each value in column1 chronologically.… Read More Time until next occurence of value in pandas dataframe

Advertisements #include <stdio.h> int avg(int []); void main(){ int average; int marks[5]={10,15,20,30,45}; printf("%d\n",sizeof(marks)); // answer is 20(as expected) avg(marks); } int avg(int marks[]){ int sum=0; printf("%d\n",sizeof(marks)); // answer is 8(why???) } In this code, I was trying to print the sizeof the integer pointer marks. When I print the sizeof the marks inside the main… Read More sizeof() gives different results for the same object