Normally, I may use the following expression to define a variable in bash as the number
var='3'
How could I associate the variable with the random value, e.g. from 1 to 6, which could be assigned each time in the for loop:
for var ...; do
print $var
done
Assuming that in each iteration, the var should be randomly selected from 1 to 6.
>Solution :
I’m not sure if your question is about generating the random number
$ echo $(( RANDOM % 6 + 1 ))
4 # results may vary
or getting a sequence of random numbers. A C-style for loop would probably be simplest.
# Roll a 6-sided dice 5 times.
for ((n=0; n<5; n++, var=RANDOM%6+1)); do
echo $var
done
The third expression makes use of the , operator, so that both n++ and var=RANDOM%6+1 are evaluated following each execution of the body of the loop.