Breaking down a number into digits – C

I’m trying to create a program that breaks down a number into its component digits.

The code I’ve written so far is as follows:

#include <stdio.h>

int main() {

int num;
int digits;
int count = 1;

printf("Insert a positive number: ");

do {

    scanf("%d", &num);

} while (num <= 0);

printf("In digits... \n");

// Number in digits
while (num != 0) {
    digits = num % 10;
    printf("Digit %d --> %d \n", count, digits);
    num /= 10;
    count++;
}

}

The digits of the number are printed correctly, but in reverse order!

Insert a positive number: 345
In digits...
Digit 1 --> 5
Digit 2 --> 4 
Digit 3 --> 3 

I can’t figure out how to fix this, can anyone help me?

>Solution :

Using your code plus code available on https://www.geeksforgeeks.org/c-program-to-print-all-digits-of-a-given-number/ (google is your friend!)

#include <stdio.h>
#define MAX 100
  
// Function to print the digit of
// number N
void printDigit(int N)
{
    // To store the digit
    // of the number N
    int arr[MAX];
    int i = 0;
    int j, r;
  
    // Till N becomes 0
    while (N != 0) {
  
        // Extract the last digit of N
        r = N % 10;
  
        // Put the digit in arr[]
        arr[i] = r;
        i++;
  
        // Update N to N/10 to extract
        // next last digit
        N = N / 10;
    }
  
    // Print the digit of N by traversing
    // arr[] reverse
    for (j = i - 1; j > -1; j--) {
        printf("%d ", arr[j]);
    }
}
  
// Driver Code
int main()
{
    int N;
    printf("Insert a positive number: ");

do {

    scanf("%d", &N);

} while (N <= 0);

printf("In digits... \n");
  
    printDigit(N);
    return 0;
}