Filter array of objects by property with array of strings with an array of strings

So I have data that looks like this:

    const data = [
      { foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"] },
      { foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"] },
      { foo: []},
      { foo: ["0001|main|0001", "0001|main|0012", "0001|main|0022"] },
    ];

And I need to filter it with an array of strings that looks like this:

let selections = ["0014", "0016"];

I need to match the items with the same last for numbers only in the data,
I currently have this which sort of works:

data.filter((item) => {
 if(!item.foo.length) return false;
 return selections.every((id) => item.foo.split('|')[2] === id)
});

The issue I’m having that when selecting two IDs like above it returns nothing.
I was expecting the return value to be this:

[
 {foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"]},
 {foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"]},
]

I works fine when selection has only one string in it. I think its searching for items that match both strings in the selection.

Any help would be appreciated!

>Solution :

Since you want

["0001|main|0014", "0001|main|0018", "0001|main|0019"]

to be included, it sounds like you need at least one of the selections to match, rather than every selection to have a match. So, use .some instead of .every.

const data = [
  { foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"] },
  { foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"] },
  { foo: []},
  { foo: ["0001|main|0001", "0001|main|0012", "0001|main|0022"] },
];
const selections = ["0014", "0016"];

const result = data.filter(
  ({ foo }) => selections.some(
    sel => foo.some(
      str => str.endsWith(sel)
    )
  )
);
console.log(result);