How to get a file's name without its extension or to load the entire path with the file without the file's extension?

I have the following following String Array:

from tkinter import filedialog as fd

pathName = fd.askopenfilename(filetypes=[('Python file','*.py')])

Output

#pathName = 'C:\Users\User\Desktop\my_program.py  

Is there a way to extract the name of my file? In this example I would want the output to be "my_program"

Or a better solution for me would be to load directly file path without the file’s extension. I need ti pathName to be ‘C:\Users\User\Desktop\my_program’

I tried using tkinter’s fd.askopenfilename but it always gets the file extension too.

>Solution :

Is there a way to extract the name of my file?

You might use os.path.splitext for that purpose

import os
filename = "file.txt"
name, ext = os.path.splitext(filename)
print(name)  # file
print(ext)  # .txt