How to get entries of array with separated by string in one line?

I have this data

[[ 2.696000e+00  0.000000e+00  0.000000e+00  0.000000e+00]
 [ 2.577000e+00  0.000000e+00  0.000000e+00  0.000000e+00]
 [ 0.000000e+00 -2.560096e+03  0.000000e+00  0.000000e+00]
...

and want to print it as such, for each row

2.696000e+00 & 0.000000e+00 & 0.000000e+00 & 0.000000e+00 //
2.577000e+00 & 0.000000e+00 & 0.000000e+00 & 0.000000e+00 //
...

I have done is

for k in range(1):
for i in range(len(data[k])):
    print(data[k][i],'&')
    if i == len(data[k])-1:
        print(data[k][i],'//')

Which outputs

2.696 &
0.0 &
0.0 &
0.0 &
0.0 //

How to get rid of the new line between each entry of the row?

>Solution :

You can use str.join to join the numbers by & and then print // as last string:

data = [
    [2.696000e00, 0.000000e00, 0.000000e00, 0.000000e00],
    [2.577000e00, 0.000000e00, 0.000000e00, 0.000000e00],
    [0.000000e00, -2.560096e03, 0.000000e00, 0.000000e00],
]

for row in data:
    print(' & '.join(map(str, row)), '//')

Prints:

2.696 & 0.0 & 0.0 & 0.0 //
2.577 & 0.0 & 0.0 & 0.0 //
0.0 & -2560.096 & 0.0 & 0.0 //