How to get string between 2 defferent quotes

I trying to get device addres from scanimage -L which return

device `canon_dr:libusb:003:004' is a CANON DR-C125 scanner

Thanks.

I come up with this

grep -Po '`\K[^']+'

but dont understend how to properly isolate special symbols

>Solution :

You can use

grep -Po "\`\\K[^']+"

Note that inside the double quoted string literal, the backtick and backslash need escaping.

You can also use awk here:

awk -F"[\`']" '{print $2}'

See the online demo:

#!/bin/bash
s='device `canon_dr:libusb:003:004'"'"' is a CANON DR-C125 scanner'
grep -Po "\`\\K[^']+" <<< "$s"
# => canon_dr:libusb:003:004
awk -F"[\`']" '{print $2}' <<< "$s"
# => canon_dr:libusb:003:004