I need a list of top-level directories with zero files. Specifically, they can contain subdirectories provided they are empty. Here’s what I’ve tried and the issues with each:
find . -maxdepth 1 -type d -empty
This does not show directories with subdirectories — also with zero files.
It skips structures like the following:
Top-level-dir ( 0 files ) => 2nd-level dir ( 0 files )
find . -type f | cut -d/ -f2 | sort | uniq -c | sort -nr
The above line is great but it skips empty top-level directories containing subdirectories — if those subdirs are empty as well. I should see all top-level directories in the output and I’m only seeing directories with files. I’m looking for a solution that will print directories with 0 files in addition to the file count of other top-level directories.
The correct solution will include top-level directories with 0 files — even if they contain subdirectories, provided all subdirectories contain 0 files as well.
Example output:
- dir1 0
- dir2 5
- dir3 0
- dir4 26
…etc.
>Solution :
I think this does what you want:
find * -maxdepth 0 -type d \
-exec sh -c 'echo -n "{}: "; find "{}" -type f -print | wc -l' \;
find * -maxdepth 0 -type d generates a list of top-level directories. For each directory, we run the command passed as the argument to -exec. In this command ,{} is substitute by the name of a directory.
Output will look something like:
./dir1: 0
./dir2: 2
./dir3: 33
./dir4: 0
./dir5: 62
Etc.