I’m trying to send some data from inputs to the database. Everything works (data is sent), but there is an error:
"Undefined array key "name" in C:\xampp\htdocs\whatever.php on line 42" and
"Undefined array key "type" in C:\xampp\htdocs\whatever.php on line 43".
Here is my code:
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('#form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'whatever.php',
data: $('form').serialize(),
success: function () {
document.getElementById("text").innerHTML = "success";
}
});
});
});
</script>
</head>
<body>
<form id="form">
<input name="name"><br>
<input name="surname"><br>
<input name="submit" type="submit" value="Submit">
<p id="text">placeholder</p>
</form>
</body>
</html>
<?php
$con = mysqli_connect("localhost", "root", "", "base");
$name = $_POST["name"];
$type = $_POST["surname"];
$date = date("d.m.Y, G:i");
$sql = "INSERT INTO product(`name`, `surname`, `date`) VALUES('$name', '$surname', '$date')";
$var = mysqli_query($con,$sql);
mysqli_close($con);
?>
I was trying a few things, but nothing worked. I would appreciate some help to fix this, thank you!
>Solution :
using isset to check whether there is a key or not.
isset($_POST["name"]) ? $_POST["name"] : null;