Print line above specific string from txt file

I have txt file contains data, i want to loop over file and print only line above "City" word.

Ex of txt file:

NEW FUSTAT TOURS
City
USA
Addres
napolean
Phone Number
************
Email
***************
PACKAGES
Test TOURS
City
UK
Addres
napolean
Phone Number
************
Email
***************
PACKAGES

Result Expected:

NEW FUSTAT TOURS
Test TOURS

I tried:

with open('dd.txt', 'r', encoding="utf-8") as f:
    input_file = f.readlines()
    for i, line in enumerate(input_file):
        if 'City' in line:
            f1 = (input_file[:i])
            f2 = str(f1)
            f3 = (f2.replace("['", ''))
            f4 = (f3.replace("\\n']", ''))
            print(f4)

Result:

NEW FUSTAT TOURS
NEW FUSTAT TOURS\n', 'City\n', 'USA\n', 'Addres\n', 'napolean\n', 'Phone Number\n', '************\n', 'Email\n', '***************\n', 'PACKAGES\n', 'Test TOURS

Any kind of help please?

>Solution :

with open('dd.txt', 'r', encoding="utf-8") as f:
    line = ''
    for next_line in f:
        if next_line.startswith('City'):
            print(line)
        line = next_line.strip()

EDIT:

with open('dd.txt') as f, open('out.txt', 'w') as f_out:
    line = ''
    for next_line in f:
        if next_line.startswith('City'):
            f_out.write(line)
        line = next_line