I declared _auth and called it in the register button, so it takes me to another screen
but I am receiving a warning that says;
"The operand can’t be null, so the condition is always true."
Please help me solve this problem, I really do not understand the problem at all.
final _auth = FirebaseAuth.instance; //This is where I declared the auth variable
late String email;
late String password;
RoundedButton(
color: Colors.blueAccent,
title: 'Register',
onPress: () async {
try {
final newUser =
await _auth.createUserWithEmailAndPassword(email: email, password: password);
if (newUser != null) { //This is where the warning comes from
if (!mounted) return;
Navigator.pushNamed(context, ChatScreen.id);
}
} catch (e) {
print(e);
}
},
),
>Solution :
the await _auth.createUserWithEmailAndPassword(email: email, password: password) will return an UserCredential object, which it will never be null, so making an if else condition over it doesn’t do anything really since the newUser != null will always equals to true.
the piece of code you wrote is equivalent to this:
final _auth = FirebaseAuth.instance; //This is where I declared the auth variable
late String email;
late String password;
RoundedButton(
color: Colors.blueAccent,
title: 'Register',
onPress: () async {
try {
final newUser =
await _auth.createUserWithEmailAndPassword(email: email, password: password);
if (!mounted) return;
Navigator.pushNamed(context, ChatScreen.id);
} catch (e) {
print(e);
}
},
),
I’m assuming that you want to catch exceptions/erros that might be thrown from this auth operation like an invalid-email, weak-password, email-already-in use, for that you need to catch with the special Exception class of Firebase Auth, the FirebaseAuthException, so your code should be like this now:
late String email;
late String password;
RoundedButton(
color: Colors.blueAccent,
title: 'Register',
onPress: () async {
try {
final newUser =
await _auth.createUserWithEmailAndPassword(email: email, password: password);
if (!mounted) return;
Navigator.pushNamed(context, ChatScreen.id);
} on FirebaseAuthException catch (e) {
print(e.code);
print(e.message);
}
},
),
Hope this helps.