Regex: Match between delimiters (a letter and a special character) in a string to form new sub-strings

I was working on a certain problem where I have form new sub-strings from a main string.

For e.g.
in_string=ste5ts01,s02,s03

The expected output strings are ste5ts01, ste5ts02, ste5ts03

There could be comma(,) or forward-slash (/) as the separator and in this case the delimiters are the letter s and ,

The pattern I have created so far:

pattern = r"([^\s,/]+)(?<num>\d+)([,/])(?<num>\d+)(?:\2(?<num>\d+))*(?!\S)"

The issue is, I am not able to figure out how to give the letter ‘s’ as one of the delimiters.

Any help will be much appreciated!

>Solution :

You might use an approach using the PyPi regex module and named capture groups which are available in the captures:

=(?<prefix>s\w+)(?<num>s\d+)(?:,(?<num>s\d+))+

Explanation

• = Match literally
• (?<prefix>s\w+) Match s and 1+ word chars in group prefix
• (?<num>s\d+) Capture group num match s and 1+ digits
• (?:,(?<num>s\d+))+ Repeat 1+ times matching , and capture s followed by 1+ digits in group num

Example

import regex as re

pattern = r"=(?<prefix>s\w+)(?<num>s\d+)(?:,(?<num>s\d+))+"
s="in_string=ste5ts01,s02,s03"

matches = re.finditer(pattern, s)
for _, m in enumerate(matches, start=1):
    print(','.join([m.group("prefix") + c for c in m.captures("num")]))

Output

ste5ts01,ste5ts02,ste5ts03