remove mixed new line characters and digits

Let’s say I have this string list:

a = ['6306\nHLIAN\nVARIOUS',
 '10215\nSPINA',
 '10279\nPIPERI-\nΜYTER',
 '38003\nCORN\nSWEET',
 '10234ROKA',
 '10232\nANTH',
 '8682PIPER\nYPAITH',
 '8676\nMAROYL',
 '10211\nΚAROT\nROOT',
 '8685AGG\nYPAU']

I want to remove the digits and keep the first piece of words. So, I want result:

['HLIAN',
 'SPINA',
 'PIPERI',
 'CORN',
 'ROKA',
 'ANTH',
 'PIPER',
 'MAROYL',
 'ΚAROT',
 'AGG']

I tried something like this:

from string import digits

def clean_list(data):
    remove_digits = str.maketrans('', '', digits)
    no_digs =  [s.translate(remove_digits) for s in data]
    results = []
    for x in no_digs:
        if '\n' in x:
            if x.count('\n') == 2:                
                results.append(x.split('\n')[-2])
            elif x.count('\n') == 1:
                results.append(x.split('\n')[1])
        else:
            results.append(x)
    return results

and I am receiving:

['HLIAN',
 'SPINA', 
'PIPERI-', 
'CORN',
 'ROKA', 
'ANTH', 
'YPAITH',
 'MAROYL',
 'ΚAROT', 
'YPAU']

I can’t catch the '8682PIPER\nYPAITH', and '8685AGG\nYPAU' because they have one \n and two words between.

Also, it would be nice if the 'PIPERI-' would come without the - symbol (it can be done in a next step though).

>Solution :

Just strip() the strings after you remove the digits and take the first string after splitting by \n

def clean_list(data):
    remove_digits = str.maketrans('', '', digits)
    no_digs = [s.translate(remove_digits).strip() for s in data]
    results = [x.split('\n')[0] for x in no_digs]
    return results

You can add replace('-', '') to the results of the split to get rid of the -.

results = [x.split('\n')[0].replace('-', '') for x in no_digs]