I use a library which has these definitions typedef void (*CallbackFunction) (ESPRotary&); void ESPRotary::setChangedHandler(CallbackFunction f) { … } When I try to use the setChangedHandler function I get an issue that the definition of my callback is wrong. #pragma once #include "ESPRotary.h" class MyUsermod : public Usermod { private: ESPRotary r = ESPRotary(13, 12); public:… Read More Callback definition is incompatible
void printLCD(int col, int row , const char *str) { for(int i=0 ; i < strlen(str) ; i++){ lcd.setCursor(col+i , row); lcd.print(str[i]); } } void loop(){ lightAmount = analogRead(0); // Here printLCD(0, 0, printf("Light amount: %d", lightAmount )); } I’m newbie to c language for arduino project. I want to show "Light Amount: 222" to… Read More How to pass variable to const char type?
I have a problem with the initialization with various parameters in my function. It works if I have created an array int params [] = {…}. However, it doesn’t work if I want to write the parameters directly into the function. declaration (in the .h) void phase_an(int led[]); in the .cpp void RS_Schaltung::phase_an(int led[]) {… Read More Output parameters with arrays in one function with Arduino and C ++
This is a function to convert 1 digit number to 3 digit. For example convert ‘2’ to ‘002’. void loop() { int x = convertdigit(time); } void convertdigit(int num){ char buffer[50]; int n; n=sprintf (buffer, "%03d",num); return buffer; } Error: void value not ignored as it ought to be /sketch/sketch.ino: In function ‘void loop()’: /sketch/sketch.ino:33:30:… Read More error: void value not ignored as it ought to be in Arduino
I have two functions in C library that I am making. One is a setup function, other is a function that does some operations. I want the second operations function to print an error if the setup function has not run before it. What would be the best way to do this? Here is what… Read More Show error in function if some other function has not run before it
How only to print the module name with ModuleNotFoundError arguments in python. my code: try: import requests except ModuleNotFoundError as error1: print(error1) In this case I am getting output as below: No module named ‘requests’ I want to be printed only the name of the module that met the exception. output I need: ‘requests’ Regards,… Read More how to get only the module name ModuleNotFoundError