I would like to create a column that is the result of boolean logic of list stored in other column. import pandas as pd import numpy as np d = {‘202201’: [7180516.0, 4868058.0], ‘202202’: [433433740.0, 452632806.0], ‘202203’: [5444119.0, 10000000.0]} df = pd.DataFrame(data=d) #Storing Values in List df[‘seq’] = df.agg(list, axis=1) #Or #df[‘seq’] = df.agg(np.array, axis=1)… Read More Applying conditional statements on lists stored in Dataframe cell

After merging two DF’s I have the following dataset: DB_ID x_val y_val x01 405 407 x01 405 405 x02 308 306 x02 308 308 x03 658 658 x03 658 660 x04 None 658 x04 None 660 x05 658 660 x06 660 660 The y table contains multiple values for the left join variable (not included… Read More Removing duplicates based on matching column values with boolean indexing

Is there a shortcut for the following evaluation? One where I do not need to specify value a twice? (a && b || a && c) Thank you. 🙂 >Solution : This should work for you: (a && (b || c))

I have listA=[[0,1],[1,2]], and listB=[[0,1,2],[0,1,3],[0,2,3],[0,2,4]]. I want to find all elements b from listB such that b⊆a doesn’t hold and a⊆b doesn’t hold for all elements a from listA. Put it another way, my desired output is: listC=[[0,2,3],[0,2,4]]. I tried the following codes: import numpy as np listA=[[0,1],[1,2]] listB=[[0,1,2],[0,1,3],[0,2,3],[0,2,4]] listC=[b for b in listB if… Read More What's wrong with this list comprehension?

Anyone can enlighten me on why -5<-2<-1 returns 0 in C when I would expect it to return 1(True)? printf("%d", -5<-2<-1); >Solution : This expression -5<-2<-1 is equivalent to ( -5<-2 ) < -1 because the operator < evaluates left to right. As -5 is less than -2 then the value of the sub-exoression (… Read More Why is this inequality False in C?