You see I have this code. (https://jsfiddle.net/kg4f2bu0/). Inside my iterate function I use a label for my loop, because I want to break it if it meets a condition. The condition gets checked inside the callback function. I want to break the for..of loop inside my callback function (compare). But it doesn’t recognise the statement… Read More How to make another function aware of the loop name, so it can break it?
I have here two snippets of code, one using traditional for loop and the other using for…of loop. export function spinWords(words: string): string { const singleWords: string[] = words.split(‘ ‘); for (let i = 0; i < singleWords.length; i++) { if (singleWords[i].length >= 5) { singleWords[i] = singleWords[i].split(”).reverse().join(”); } } return singleWords.join(‘ ‘); } export… Read More Difference between for and for..of loops' output in a specific example
Is it possible to loop over part of an iterator with for…of without closing the iterator when I break the loop? Example: function* numbers(i=0){ while(true) yield i++; } let nums=numbers(); // this loop prints numbers from 0 to 3 for(const n of nums){ if(n>3) break; console.log(n); } // this loop doesn’t print anything because `nums`… Read More for…of an iterator without closing it
I’ve list of users: const users = [ { id: 1, name: “Leanne Graham”, phone: “1-770-736-8031 x56442”, }, { id: 2, name: “Ervin Howell”, phone: “010-692-6593 x09125”, }, { id: 3, name: “Leanne Graham”, phone: “1-463-123-4447”, }, { id: 4, name: “Leanne Graham”, phone: “493-170-9623 x156”, }, { id: 5, name: “Chelsey Dietrich”, phone: “(254)954-1289”,… Read More How to make name of users uniques by adding number of occurrence?
Take a close look at code function* NinjaGenerator() { yield “yoshi”; return “Hattori”; } for (let ninja of NinjaGenerator()) { console.log(ninja); } // console log : yoshi Why "Hattori" is not logged ? Where as when we iterate over iterator using iterator.next() it show that value. function* NinjaGenerator() { yield “yoshi”; return “Hattori”; } let… Read More In JavaScript, Iterating over generator using for-of loop ignore return statement why?
I know how to skip first iteration in javascript foreach loop dataObject.slice(1).forEach((row) => {}); I want to know how to do the same thing using for of loop in javascript, please help me, thanks for( const row of dataObject ) >Solution : The same way you’re skipping it with forEach – replace the dataObject expression… Read More How to skip first iteration in javascript for-of loop