There is a stack containing a long-sized range, and you want to multiply two values ​​by popping them from the stack. Stack<Long> s = new Stack<>(); s.push(1000000000); s.push(1000000000); long result = (long) s.pop() * (long) s.pop(); However, doing such an operation gives an error. Exception in thread "main" java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long… Read More Why does a compilation error occur when declaring a stack containing a Long object in Java, popping a number, and then casting it to long?

im trying to learn how to reverse a number but came across a problem about this Do-While loop. Specifically while (n1). Usually i just see people put in a condition with about comparison. #include <iostream> #include <conio.h> using std::cout; using std::cin; using std::endl; int main() { long int n1, n2, Rinteger = 0; cout <<… Read More what does this variable name do in the Do-While loop expression and what is the meaning of its existence in it?

I was trying to answer this leetcode problem of Adding two Numbers in a String and returning a result. the code works fine for basic test cases, but in the hidden test cases the code fails to return a correct output and instead returns some unrelevent value. im having a hard time understanding that, could… Read More I am trying to Add two Numbers in a String and Return their summation , but facing an error in the hidden testcase

This is all my code. I compiled it and tested it with the word ‘Hello’ , it encrypts and decrypts correctly. It doesnt seem to work for bigger values. And thanks in advance for everyone’s answers. All the function are compiled and tested. (I am just gonna type a few more words so they let… Read More how to convert long to char in C?

How do I preserve precision in my sum output. I think that what is happening is that the precision is exactly the same, but one option chooses to round. public class Main { public static void main(String[] args) { final long seconds = 1637208584L; final long micro_of_second = 795307; final long sum = seconds +… Read More How to add a long and preserve precision when printing