an alternative to (any) function

I’m currently working on a password validity code, but I didn’t learn the (any) function yet so I should not use it
I’m looking for a different way to make the code work and check if there is lowercase, uppercase, and digits in the password. I thought about using a loop that checks each character, but I couldn’t do it since I’m still learning loops

def main():
    P1 = str(input("Enter a password: "))
    if checkPassword(P1) == True:
        P2 = str(input("Confirm the Password: "))
        if P1 != P2:
            print("Password does not match!")
            main()
        else:
            print("The password is valid!")


def checkPassword(Pass):
    if len(Pass) < 8:
        print("Invalid Password: Should be at least 8 characters")
        return False
    if not any(char.isdigit() for char in Pass):
        print("Invalid Password: Should contain at least one digit")
        return False
    if not any(char.isupper() for char in Pass):
        print("Invalid Password: Should contain at least one uppercase character")
        return False
    if not any(char.islower() for char in Pass):
        print("Invalid Password: Should contain at least one lowercase character")
        return False
    return True

main()

>Solution :

You could just make your own any function and then use that if you’d prefer,

def my_any(iterable, predicate):
    for item in iterable:
        if predicate(item):
              return True
    return False


if not my_any(Pass, lambda char: char.isdigit()):
    print("Invalid Password: Should contain at least one digit")
    return False

without a lambda, you need to figure out what errors have been triggered. and then use your if statement after that

digit_found = False
lower_found = False
upper_found = False
for char in Pass:
     if char.isdigit():
          digit_found = True
     elif char.isupper():
          upper_found = True

if not digit_found:
    print("Invalid Password: Should contain at least one digit")
    return False