Any python trick for flattening a dictionary and sorting it all at once?

I have this dictionary:

s = [{"label":["College Name"],"points":[{"start":939,"end":956,"text":"Kendriya Vidyalaya"}]},{"label":["College Name"],"points":[{"start":883,"end":904,"text":"Woodbine modern school"}]}]

I can sort it on start like this:

for annotation in sorted(s, key = lambda tup: tup['points'][0]['start']):
    print(annotation)

At the end of the day I need label, start and end. I know that I can access annotation in the loop and get to all the values I need, but then I’m pulling out the start point twice.

Is there any cool python trick to unpack values from a dictionary and sort on one of them all at once?

>Solution :

You mean like this?

for annotation in sorted(s, key = lambda tup: tup['points'][0]['start']):
    print(annotation["label"],annotation["points"][0]["start"],annotation["points"][0]["end"])

Or, only having to identify start by name once:

for annotation in sorted([(x["label"][0],x["points"][0]["start"],x["points"][0]["end"]) for x in s], key = lambda tup: tup[1]):
    print(annotation)