Append 1 for the first occurence of an item in list p that occurs in list s, and append 0 for the other occurence and other items in s

I want this code to append 1 for the first occurence of an item in list p that occurs in list s, and append 0 for the other occurence and other items in s.

That’s my current code below and it is appending 1 for all occurences, I want it to append 1 for the first occurence alone. Please, help

s = [20, 39, 0, 87, 13, 0, 23, 56, 12, 13]
p = [0, 13]
bin = []

for i in s:
        if i in p:        
            bin.append(1)      
        else:
            bin.append(0)
   

print(bin)

# current result [0, 0, 1, 0, 1, 1, 0, 0, 0, 1]
# excepted result [0, 0, 1, 0, 1, 0, 0, 0, 0, 0]

>Solution :

The simplest solution is to remove the item from list p if found:

s = [20, 39, 0, 87, 13, 0, 23, 56, 12, 13]
p = [0, 13]

out = []
for i in s:
    if i in p:
        out.append(1)
        p.remove(i)
    else:
        out.append(0)

print(out)

Prints:

[0, 0, 1, 0, 1, 0, 0, 0, 0, 0]