Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

array.filter is returning entire object instead of just one value

I have a simple function that is filtering an array.

I only want the string value, not the entire object.

Why is the entire object coming back and not just the string?

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

I get the desired output if I switch the return to a console.log()

Any ideas?

Here is the code

 const Array2 = [
        { header: 'First name', HeaderIndex: 0},
        { header: 'Last name', HeaderIndex: 1},
        { header: 'Company', HeaderIndex: 2},
        { header: 'Favorite food', HeaderIndex: 3},
        { header: 'Favorite color', HeaderIndex: 4},
    ]

const testing = Array2.filter((obj) => { if(obj.HeaderIndex === 1) { return obj.header } } )

console.log(testing)

// gives undesired output

[{…}]
0: {header: 'Last name', HeaderIndex: 1}
length: 1
[[Prototype]]: Array(0)



const testing = Array2.filter((obj) => { if(obj.HeaderIndex === 1) { console.log(obj.header)} } )

// gives desired output

"Last name"

my problematic output is below, I just want to return the string

[{…}]
0: {header: 'Last name', HeaderIndex: 1}
length: 1
[[Prototype]]: Array(0)

Update*

I accepted the answer from Mayur because it solved my problem in a bigger use case. Here is my bigger use case below where I needed to merge these two arrays depending on Array1 index needing to match HeaderIndex from Array2



const Array1 = [ 
    ['Alex', 'Boe', 'MeowWolf', 'pizza', 'pink'],
    ['Arron', 'Coe', 'Kmart', 'tofu', 'purple'],
    ['Jane', 'Doe', 'Sears', 'tacos', 'orange'],
    ['John', 'Eoe', 'YugiOh', 'blueberries', 'magenta'],
    ['Suzie', 'Boe', 'Toyota', 'steroids', 'blue']
    ]
    
    
    const Array2 = [
        { header: 'First name', HeaderIndex: 0},
        { header: 'Last name', HeaderIndex: 1},
        { header: 'Company', HeaderIndex: 2},
        { header: 'Favorite food', HeaderIndex: 3},
        { header: 'Favorite color', HeaderIndex: 4},
    ]

const testResult = Array1.map((arr) => arr.map((string) => { return  {"ChosenHeader": Array2.filter((obj) => obj.HeaderIndex === arr.indexOf(string))[0]?.header, "content": string}} ))

console.log(testResult)


// desired output



0: {ChosenHeader: 'First name', content: 'Alex'}
1: {ChosenHeader: 'Last name', content: 'Boe'}
2: {ChosenHeader: 'Company', content: 'MeowWolf'}
3: {ChosenHeader: 'Favorite food', content: 'pizza'}
4: {ChosenHeader: 'Favorite color', content: 'pink'}

>Solution :

Because filter() always return an array. you want filter from return array. using [0].header You can do it !

Try this code it’s work

 const testing = Array2.filter((obj) => obj.HeaderIndex === 1)[0].header;
    console.log(testing, 'testing')
Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading