Given the following array:
x = np.zeros((1, 5))
x
# array([[0., 0., 0., 0., 0.]])
I’d like to be able to create array([[0., 3., 1., 0., 8.]]) using something such as:
values = [3, 1, 8]
indices = [1, 2, 4]
y = x.iloc[indices] = values
I appreciate that this doesn’t work – but I’m not sure what an idiomatic approach to this sort of thing in numpy would be.
The following works, but it doesn’t seem like it’s a sensible approach using numpy:
values = [3, 1, 8]
indices = [1, 2, 4]
for i, v in zip(indices, values):
row[i] = v
>Solution :
Just move the indexer to the second position (because you’re modifying values in the second dimension):
x[:, indices] = values
Output:
>>> x
array([[0., 3., 1., 0., 8.]])