i am trying to compare the hash of a copied file with bash but the condition is not working .
└──╼ $bash check-256.sh cal.sh 2cal.sh
ea8f4b5acdeb26015661ee27c9000af97691a0fd715be94b2b3eda6a3d02c789 cal.sh
ea8f4b5acdeb26015661ee27c9000af97691a0fd715be94b2b3eda6a3d02c789 2cal.sh
—
#!/bin/bash
First_file=$(sha256sum $1)
Second_file=$(sha256sum $2)
echo "$First_file"
echo "$Second_file"
[ "$First_file" == "$Second_file" ] && echo "Pass" || echo "Fail"
>Solution :
The condition fails, because the resulting strings are actually not the same. You need to cut out the hash by using the cut command.
#!/bin/bash
First_file=$(sha256sum $1 | cut -d' ' -f1)
Second_file=$(sha256sum $2 | cut -d' ' -f1)
echo "$First_file"
echo "$Second_file"
[ "$First_file" == "$Second_file" ] && echo "Pass" || echo "Fail"
cut -d' ' -f1
- -d specifies the delimiter. In this case we use a single space
- -f1 selects the field of the output. Here we want to only have the first field, which is the hash