best way of counting number of items based on condition python

Hi guys I have multiple conditions to check on a array of objects for example :

My sample array is like this

[{"id":1 , "type":"viw"},{"id":1 , "type":"edit"},{"id":1 , "type":"crt"}]

as these records will be in 10000’s I want to calculate total sum of these in best way possible .

Currently doing like this

   view_count = [element for element in user_record if element['type'] == "viw"  ]
   edit_count = [element for element in user_record if element['type'] == "edit"]
   crt_count = [element for element in user_record if element['type'] =="crt"]

   and then len(crt_count) ,len(edit_count) ,len(view_count) 

which seems to me a little expensive . kindly guide can I do it in optimize way ?

and 2nd question can I use OR condition with if in this list comprehension ?

>Solution :

Just collect each of the ‘types’ into a dictionary key and count them with it’s value

result = {}
for element in user_record:
   try:
        result[element["type"]] += 1
   except KeyError: 
        result[element["type"]] = 1

per comment from @Not A Robot :
"another way for essentially the same idea:"

collections.Counter(map(operator.itemgetter('type'), my_list))

Second Question: Answer is yes you can use or like this:

edit_count = [element for element in user_record if element['type'] == "edit" or element['type'] == 'viw']