Best way to loop through an array and return the sub arrays that match the first 2 values

Let’s say I have 4 arrays:

var arrays =  [
    [1, 2, 1],
    [1, 3, 4],
    [1, 2, 3],
    [0, 2, 2]
];

And I want to return the child/sub arrays that start with both 1 and 2, what type of loop would I need?

Currently, this is what I have:

var arrays =  [
    [1, 2, 1],
    [1, 3, 4],
    [1, 2, 3],
    [0, 2, 2]
];
        
var selected = [1, 2]; // These are the values that need to match
var result = [];
for (var i = 0; i < selected.length; i++) {
    for (var j = 0; j < arrays.length; j++) {
        if (arrays[i][j] === selected[i]) {
            result.push(arrays[i]);
        }
    }
}

When there’s more than 1 value in the selected array, it seems to return all the ones that match 2 on the second index, so the result would be:

[
    [1, 2, 1],
    [1, 2, 3],
    [0, 2, 2]
]

The loop needs to ensure that on the second iteration it’s making sure the first value is still true, as my intended result would be:

[
    [1, 2, 1],
    [1, 2, 3]
]

Please someone help me, I’ve had my head trying hundreds of different loop and checks variations for 2-3 days.

Thanks so much!!

Jake

>Solution :

Here is another approach where you turn both arrays to string and check it those inner arrays start with selected array.

var arrays = [
  [1, 2, 1],
  [1, 3, 4],
  [1, 2, 3],
  [0, 2, 2]
];

var selected = [1, 2];
const result = arrays.filter(e => e.toString().startsWith(selected.toString()))
console.log(result)