C++ Reversing Order of Values in a Vector without the use of a reiterator

Read integers from input and store each integer into a vector until 0 is read. Do not store 0 into the vector. Then, output all values in the vector in reverse order, each on a new line.

This is the current code I used and for some reason it only outputs 2 or 3 values instead of all of them. Is there something I did wrong?

int main() {
    unsigned int i;
    int inputNum;
    vector<int> vectorNum;

    cin >> inputNum;

    while (inputNum != 0) {
        vectorNum.push_back(inputNum);
        cin >> inputNum;
    }

    for (i = 0; i < vectorNum.size(); ++i) {
        cout << vectorNum.back() << endl;
        vectorNum.pop_back();
    }

    return 0;
}

>Solution :

With this:

for (i = 0; i < vectorNum.size(); ++i) {
  cout << vectorNum.back() << endl;     
  vectorNum.pop_back();
}

the issue is that you are increasing i in the for loop, but decreasing the number of entries in the vector with pop_back(). Both things occurring will result in less items processed.

Instead of a for loop, use while() and the empty() member function:

while (!vectorNum.empty())
{
   cout << vectorNum.back() << endl;    
   vectorNum.pop_back();
}