the title says it all.
I have this function that couts the parameter:
void outlog(string par) {
std::cout << par;
}
but Par can only be a string. how can I make its type optional.
>Solution :
C++ (and many other languages) makes it available to have generic functions. Here you can read more about it: Generics in C++ Here is the sample code for your function. Note: the object should be printable (if it is a class object, it should have the << operator overloaded):
template <typename T>
void outlog(T& input){
std::cout << input;
}